
The Monty Hall Problem is a fun puzzle about probability. It comes from a game show called Let’s Make a Deal. The host of the show is Monty Hall. This problem surprises many people. It shows that probability can be tricky. Our instincts can be wrong.
In this article, we will explain the problem. We will explore its solution. We will see why it feels counterintuitive. By the end, you will understand why switching is the best choice.
Setting Up the Scenario
Imagine you are on a game show. You see three closed doors.
- Behind one door, there is a car (prize).
- Behind the other two doors are goats (losses).
The objective is to pick the door hiding the car. Here’s how the game proceeds:
- First Choice: You pick one of the three doors. Let’s say you choose Door 1.
- Monty’s Action: Monty, the host, knows what’s behind each door. He opens one of the other two doors to show you a goat.
- Decision Point: Now, you must decide. Do you want to stick with Door 1 or switch to the other unopened door?
The question: Should the contestant stick with their original choice or switch to the other door to maximize their chance of winning the car?
Understanding Probability in the Monty Hall Problem
When the game begins, you have a 1/3 chance of picking the door with the car and a 2/3 chance of picking a door with a goat. These probabilities play a central role in solving the problem.
- Initial Choice: If you choose Door #1, there’s a 1/3 probability that you picked the car and a 2/3 probability that you picked a goat.
- Monty’s Reveal: Monty then opens a door with a goat, which doesn’t change the probability of your initial choice but does provide new information that influences the outcome if you switch.
Why Switching Works
Case 1: You initially pick the car (1/3 chance).
- Monty reveals a goat behind one of the other doors.
- If you stick, you win the car. If you switch, you get a goat.
- Outcome if you switch: lose.
Case 2: You initially pick a goat (2/3 chance).
- Monty reveals the other goat (since he knows what’s behind the doors).
- If you stick, you lose. If you switch, you win the car.
- Outcome if you switch: win.
Since cases 2 and 3 together cover 2/3 of the scenarios, switching gives you a higher probability of winning the car (2/3) than sticking with your original choice (1/3).
Mathematical Verification
To reinforce this conclusion, let’s look at the problem with probability theory:
- Probability of Choosing the Car Initially (P(Car)): 1/3.
- Probability of Choosing a Goat Initially (P(Goat)): 2/3.
When Monty reveals a goat, he provides information that influences your chances. Since you had a 2/3 chance of picking a goat, this probability transfers to the other unopened door when Monty shows a goat. So, the chance of winning by switching is 2/3. This confirms that switching is the better choice.
Why Is This Counterintuitive?
Many people believe the chances are 50/50 after one door is opened. This thinking is not correct. Here are some key points to understand:
- Initial Probabilities: When you first pick a door, there is a 1/3 chance it has the car. This means there is a 2/3 chance it does not have the car.
- Information Revelation: Monty’s action of revealing a goat provides new information about the probabilities. He will always reveal a goat, which means that if your first choice was incorrect, the car must be behind the other door.
- Simulation and Experience: Many simulations show that switching wins more often. If you play many rounds, switching will win you the car about twice as often as staying with your original choice.
Implications in Decision Theory
The Monty Hall problem has significant implications in decision theory, particularly in how humans assess risk and make choices:
- Overconfidence in Intuition: People often rely on their gut feelings in decision-making, which can lead to systematic errors. The Monty Hall problem reveals that what feels right is not always statistically accurate.
- Importance of Information: The problem demonstrates how additional information can drastically change the probabilities involved in a decision. This highlights the importance of not only the decision itself but also how one interprets the information available.
- Application Beyond Games: The lessons from the Monty Hall problem extend into various fields, such as economics, psychology, and even everyday life scenarios, where choices are made based on incomplete information. Understanding conditional probabilities can improve decision-making in uncertain situations.
A Real-World Example
To illustrate the Monty Hall problem further, consider a practical scenario involving multiple rounds of the game:
Situation:
- You play 100 rounds of the game.
- You choose to switch every time.
Expected Outcomes:
- If you always switch, you should win approximately 66 out of 100 times (2/3 of the rounds).
- If you always stay, you will win approximately 33 out of 100 times (1/3 of the rounds).
This empirical evidence reinforces the mathematical reasoning behind the Monty Hall problem and highlights the reliability of the probabilities over many trials.
Conclusion
The Monty Hall Problem is an interesting study in probability. It shows how our instincts can be wrong. By analyzing the problem, we can see better ways to decide.
Understanding probability is important. It helps us see how information affects our choices. These lessons apply not just in games, but in daily life. Making informed choices can lead to better results. This is true even in uncertain situations.

The Monty Hall problem asks about the probability of an event that has not occurred: switching. But no probability distribution is provided for that. So, if the contestant decides to flip a fair coin to switch or not, the correct probability is 50-50 of winning by switching.
Unfortunately, the answer provided is about whether the car is behind the other unopened door. That probability is either 0 or 1. All relevant events related to that point in the game have occurred. Given that Monty knows which door the car is behind, clearly the probability is 1 that the car is behind that door. Also, revealing what’s behind a door does not change what was behind the door before it was opened. So, if the probability the car is behind the door that was opened is 0 after it was opened, then that was the probability before it was opened.
Reference
Kicab Castaneda-Mendez,
Mine Çetinkaya-Rundel(Column Editor) & Maria Tackett (Column Editor) (2024)
Taking a Chance in the Classroom: Puzzling Probabilities of
Probability Puzzles, CHANCE, 37:3, 60-65, DOI: 10.1080/09332480.2024.2415844 https://doi.org/10.1080/09332480.2024.2415844
Thank you for your contribution and feedback to our discussion!
Seems to me that with 100 doors, it’s not 1/3 and 2/3 but 1/100 and 99/100
It seems that the odds should always be 50/50. You are never really choosing between 3 doors. If you know the rules, that Monty is ALWAYS going to remove a goat door, you are always picking the car between 2 doors. They 3rd door is never play in play.
Hi Craig…Interesting observation! Can you elaborate on this?