**Logarithmic regression** is a type of regression used to model situations where growth or decay accelerates rapidly at first and then slows over time.

For example, the following plot demonstrates an example of logarithmic decay:

For this type of situation, the relationship between a predictor variable and a response variable could be modeled well using logarithmic regression.

The equation of a logarithmic regression model takes the following form:

**y = a + b*ln(x)**

where:

**y:**The response variable**x:**The predictor variable**a, b:**The regression coefficients that describe the relationship between*x*and*y*

The following step-by-step example shows how to perform logarithmic regression in R.

**Step 1: Create the Data**

First, let’s create some fake data for two variables: *x* and *y*:

x=1:15 y=c(59, 50, 44, 38, 33, 28, 23, 20, 17, 15, 13, 12, 11, 10, 9.5)

**Step 2: Visualize the Data**

Next, let’s create a quick scatterplot to visualize the relationship between *x* and *y*:

plot(x, y)

From the plot we can see that there exists a clear logarithmic decay pattern between the two variables. The value of the response variable, *y*, decreases rapidly at first and then slows over time.

Thus, it seems like a good idea to fit a logarithmic regression equation to describe the relationship between the variables.

**Step 3: Fit the Logarithmic Regression Model**

Next, we’ll use the **lm()** function to fit a logarithmic regression model, using the natural log of *x* as the predictor variable and *y* as the response variable

#fit the model model <- lm(y ~ log(x))#view the output of the model summary(model) Call: lm(formula = y ~ log(x)) Residuals: Min 1Q Median 3Q Max -4.069 -1.313 -0.260 1.127 3.122 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 63.0686 1.4090 44.76 1.25e-15 *** log(x) -20.1987 0.7019 -28.78 3.70e-13 *** --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 Residual standard error: 2.054 on 13 degrees of freedom Multiple R-squared: 0.9845, Adjusted R-squared: 0.9834 F-statistic: 828.2 on 1 and 13 DF, p-value: 3.702e-13

The overall F-value of the model is 828.2 and the corresponding p-value is extremely small (3.702e-13), which indicates that the model as a whole is useful.

Using the coefficients from the output table, we can see that the fitted logarithmic regression equation is:

**y = 63.0686 – 20.1987 * ln(x)**

We can use this equation to predict the response variable, *y*, based on the value of the predictor variable, *x*. For example, if *x* = 12, then we would predict that *y* would be **12.87**:

y = 63.0686 – 20.1987 * ln(12) = **12.87**

**Bonus:** Feel free to use this online Logarithmic Regression Calculator to automatically compute the logarithmic regression equation for a given predictor and response variable.

**Step 4: Visualize the Logarithmic Regression Model**

Lastly, we can create a quick plot to visualize how well the logarithmic regression model fits the data:

#plot x vs. y plot(x, y) #define x-values to use for regression line x=seq(from=1,to=15,length.out=1000) #use the model to predict the y-values based on the x-values y=predict(model,newdata=list(x=seq(from=1,to=15,length.out=1000)), interval="confidence") #add the fitted regression line to the plot (lwd specifies the width of the line) matlines(x,y, lwd=2)

We can see that the logarithmic regression model does a good job of fitting this particular dataset.

**Additional Resources**

How to Perform Simple Linear Regression in R

How to Perform Multiple Linear Regression in R

How to Perform Quadratic Regression in R

How to Perform Exponential Regression in R

How to Perform Polynomial Regression in R

Overall, the tutorial is very informative, but I have a quick question that you take 12 as an example for X so as to predict Y, but I did not understand how i will see my X value (like 12 in your example) if i am comparing two variables, here you used X,Y you have long column but you take 12 as an example not x value from x column and why we need to predict Y, please kindly elaborate it. Waiting for response. Thank you very much.

Another important thing i am trying to compare two matrices by logarithmic regression model but the code you have given in last step is to defined the x for y prediction, for example if someone have two variable to compare then how they can use code for that.

If i have variables e.g., Temperature and Species i want to compare it then how i can define the Y that is Species for X that is temperature, Really need your help.