This lesson describes how to create a confidence interval for a population proportion.

**Checking Conditions**

Before we can create a confidence interval for a population proportion, we first need to make sure the following conditions are met to ensure that our confidence interval will be accurate:

**Random:**A random sample or random experiment should be used to collect the data.**Normal:**The sampling distribution of the sample proportion needs to be approximately normal – need at least 10 expected successes and 10 expected failures.**Independent:**Individual observations are independent. If sampling without replacement, our sample size shouldn’t be more than 10% of the population.

If these three conditions are met, then we can construct a confidence interval for a population proportion.

The formula to find a confidence interval for a population proportion is:

p +/- (z critical value) * (√p(1-p) / n)

where **p** is the sample proportion and **n** is the sample size.

Let’s walk through an example of how to find a confidence interval for a population proportion.

**Example: How to Find a Confidence Interval for a Population Proportion**

There are 500 students at a certain school. The principal of the school wants to estimate what proportion of all students prefer chocolate milk over regular milk in the cafeteria. He takes a simple random sample of 50 students and finds that 20 of the students prefer chocolate milk.

**Based on this sample, find a 99% confidence interval for the proportion of students at this school who prefer chocolate milk over regular milk.**

**Solution:**

**Step 1: Identify the sample proportion.**

p = 20 / 50 = **0.4**

**Step 2:** **Find the z critical value.**

Since we are using a 99% confidence level, we need to look up (1 – 0.99)/2 = .01/2 = .005 in the body of the z table and find the corresponding z value. It turns out to be **-2.575**.

**Step 3: Find the sample standard deviation.**

√p(1-p) / n = √.4(1-.4) / 50 = **.0692**

**Step 4: Plug all of the numbers we just found into the confidence interval formula.**

p +/- (z critical value) * (√p(1-p) / n)

.4 +- (-2.575)*(.0692)

.4 +/- (.01236) =** (.2215, .5784)**

The 99% confidence interval for the proportion of students at this school who prefer chocolate milk over regular milk is **(.2215, .5784)**